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Why are there only 2 peaks in proton NMR of 2-iodopropane?

I was reading about proton NMR and was drawing high resolution spectra for some of the molecules. I have currently drawn proton NMR spectra for ethanol and ethyl benzoate and got number of peaks as expected.

But while I started drawing the first peak of the proton attached to the mid carbon or 2-iodopropane, I considered the spin-spin splitting of the 3-H atoms that are non-equivalent to the proton which is bound to that carbon having the Iodine atom. So, my expected peaks should have been 4 as per n+1 rule. But, when I crossed check from book, there was only one signal? Why is it so?

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