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What is the mechanism for this intramolecular SN1 reaction?

For this question, my professor hinted at an intramolecular reaction, and he asked us to recall the bromonium ion as well. As such, I believe the SMe group attacks the open carbocation when OTs leaves. I think I understand how the left-side enantiomer is formed: SMe attacks the open carbocation, then water attacks from the back because the front-side is occupied by the hydrogen (not shown). However, what is the mechanism for the right-side enantiomer? How does the SMe end up in front (on a wedge) along with water after hydrolysis?

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