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Finding $\lim_{x\rightarrow 0} \frac{\sin(x)-x}{x^2}$

I’m trying to find the following limit: $$\lim_{x\rightarrow 0} \frac{\sin(x)-x}{x^2}$$ I’m not allowed to use L’Hospital’s rule this moment. I tried to use the tools I have, which are $\lim_{x\rightarrow 0} \frac{\sin(x)}{x}=1$, squeeze and make substitutions, but without success. I’m asking here only a hint if it’s possible. Thanks!