Tag: b2

Split dataframe with all values in one row

Post author By Full Stack
Post date October 17, 2020
No Comments on Split dataframe with all values in one row

I got the following dataframe which is created dynamically but saves all the relevant values into one row: df +—————-+—————-+—————-+—————-+ | 1 | 2 | 3 | 4 | +—————-+—————-+—————-+—————-+ | a1, b1, c1, d1 | a2, b2, c2, d2 | a3, b3, c3, d3 | a4, b4, c4, d4 | +—————-+—————-+—————-+—————-+ I need to […]

Tags 'B':[4, all b's etc (the columns are defined and constant): +----+----+----+----+ | 1 | 2 | 3 | 4 | +----+----+----+----+ | a1 | a2 | a3 | a4 |, b1, b2, b3, c(1, c2, c3, c4, d1 | a2, d2 | a3, d3 | a4, d4 | +----------------+----------------+----------------+----------------+ I need to have all a_i values in one row, I got the following dataframe which is created dynamically but saves all the relevant values into one row: df +----------------+-----------

Mastering Development

Fast way to remove array of specific row values from 2D numpy array

Post author By Full Stack
Post date October 17, 2020
No Comments on Fast way to remove array of specific row values from 2D numpy array

I have a 2D array like this: a = np.array([[25, 83, 18, 71], [75, 7, 0, 85], [25, 83, 18, 71], [25, 83, 18, 71], [75, 48, 8, 43], [ 7, 47, 96, 94], [ 7, 47, 96, 94], [56, 75, 50, 0], [19, 49, 92, 57], [52, 93, 58, 9]]) and I want to […]

Tags -48, :, :]).any(-1).all(0)] '''def remove_nploop(data): a, 'a2':a2, 'a3':a3, 'a4':a4, 'B': [2 ** k for k in range(11, 'B': kernels[:3]}[figure], 'B':'Testing removal of large dataset'}[figure], 'B')] fig = plt.figure(figsize=(20, 'b1':b1, 'b3':b3, 'b4':b4, 'equality_check': lambda x, 'kernels': {'A': kernels, 'm1':m1, 'm2':m2, 'm3':m3, 'm4':m4} ravel_a = ne.evaluate('(a1-m1)+(a2-m2)*s1+(a3-m3)*s1*s2+(a4-m4)*s1*s2*s3', 'n_range': {'A': [2 ** k for k in range(12)], 'show_progress': False, 'title' : {'A':'Testing removal of small dataset', 'xlabel': 'Remowing n rows from n rows', "71", "s3", [ 75, ['s2', [56, 0, 1, 18, 19, 20)) for i in range(len(outs)): ax = fig.add_subplot(2, 25, 25)]}[figure], 4)) a2 = a1[np.random.randint(x, 43, 47, 49, 50, 52, 57, 57]]) Update The fastest approach is dimensionality reduction but it requires quite strict limitations of ranges of columns in general. The, 58, 7, 71]]) What is the most efficient way to do this in numpy or pandas? Expected output: np.array([[75, 8, 83, 85, 9, 9]]) and I want to remove rows that has specific values, 92, 93, 94, 96, a.tolist())) b_map = set(map(tuple, A2, a2 def build_args(figure): kernels = [remove_reducedim, A3, a4 = a.T b1, arr, axis=(0, axis=0) m, axis=0) m1, axis=0) mb, axis=0) ravel_a = np.ravel_multi_index((a-m).T, axis=0) s1, axis=1)] return a''' def remove_looped(data): a, B, b = a.astype(np.int64), b = data a, b = data dfa, b = data for arr in b: a = a[np.all(~np.equal(a, b = data return a[(a[None, b = data to_remain = [True]*len(a) a_map = list(map(tuple, b = data to_remain = [True]*len(a) ind = 0 for vec_a in a: for vec_b in b: if np.array_equal(vec_a, b.astype(np.int64) #make sure box is not too small ma, b.tolist())) for i in range(len(a)): to_remain[i] = not(a_map[i] in b_map) return a[to_remain] def remove_reducedim(data):, b2, b2=b2, b3, b4 = b.T d = {'a1':a1, d) ravel_b = ne.evaluate('(b1-m1)+(b2-m2)*s1+(b3-m3)*s1*s2+(b4-m4)*s1*s2*s3', d) return a[~np.isin(ravel_a, dfb = pd.DataFrame(a), for example: b = np.array([[56, how='left', I have a 2D array like this: a = np.array([[25, i+1) ax.grid(True, indicator=True)\ .query('_merge == "left_only"').drop(columns='_merge').values def remove_smalldata(data): a, M - m + 1) ravel_b = np.ravel_multi_index((b-m).T, M - m + 1) return a[~np.isin(ravel_a, M = np.min([ma, m2, M2-m2+1, m3, M3-m3+1, M4 = np.max([MA, m4 = np.min([ma, M4-m4+1 a1, MA = np.min(a, Mb, MB = np.min(b, None, np.max([MA, np.max(a, np.max(b, pd.DataFrame(b) return dfa.merge(dfb, ravel_b)] def remove_reducedim_boost(data): a, ravel_b)] def setup(x): a1 = np.random.randint(50000, remove_looped, remove_looped_boost, remove_pd, remove_reducedim_boost, remove_smalldata] return {'setup': setup, s1)(s1, s2)(s2, s3)(s3, s4 = M1-m1+1, size=x)] return a1, sizeX, time()-t) Output: Overall testing time: 529.2596168518066, vec_b): to_remain[ind] = False break ind += 1 return a[to_remain] def remove_looped_boost(data):, which="both") outs[i].plot() plt.show() print('Overall testing time:', y: np.array_equal(x, y)} t = time() outs = [perfplot.bench(**build_args(n)) for n in ('A'

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iptables / nftables: Forward UDP data to multiple targets

Post author By How To
Post date October 17, 2020
No Comments on iptables / nftables: Forward UDP data to multiple targets

I need to create iptables rules for the following scenario: Different hosts send UDP data to host A. The target port is 1234. Host A (8.2.3.4) redirects the received UDP data to hosts B1 (7.2.3.1), B2 (22.93.12.3), … Bn (12.42.1.3); the IP addresses are just for illustrations there. It is not about load balancing, so […]

Tags ... Bn (12.42.1.3); the IP addresses are just for illustrations there. It is not about load balancing, ... Bn do not have to be able to answer back I've tried to solve this with PREROUTING / mangle: HOST_A=8.2.3.4 HOST_B1=7.2.3.1 HOST_B2=22.9, ... Bn do not seem to receive the data. Does anyone know what is wrong? Debugging is actually quite tricky (I found not really a way to do it, ... Bn must receive all packages. Therefore, ... Bn The hosts B1, ... Bn) and source IP (host A) I cannot change anything on the initial hosts which send data to host A I cannot change anything on the targ, b2, B2 (22.93.12.3), host A has to duplicate the packages. The forwarded packages must have the correct target IP (B1, I need to create iptables rules for the following scenario: Different hosts send UDP data to host A. The target port is 1234. Host A (8.2.3, so every host B1

Mastering Development

Filter dataframe by logic

Post author By Full Stack
Post date October 12, 2020
No Comments on Filter dataframe by logic

I have this dataframe: MAT MAT_IN SER D8 0 X A1 Yes – 1 X A2 No X 2 X A3 No X 3 X A4 Yes X 4 Y B1 No – 5 Y B2 No – 6 Y B3 No – 7 Y B4 No – 8 Y B5 No – Where I […]

Mastering Development

How to prettify JSON.stringify() partially?

Post author By Full Stack
Post date October 7, 2020
No Comments on How to prettify JSON.stringify() partially?

Users can download JSON files from our application, which I want to prettify for easier debugging than if all is in one line. However this increases the file size by nearly 40% even if the indentation is just a single tab or space. As a compromise, I want to exclude all values with e.g. the […]

Tags '\t'); document.getElementById("json").innerText = json; How can I prevent this escap, '\t'); However the values for the "large" keys ends up escaped: data = { "small": { "a": 1, "d":"the \"large\" object should not be prettified"} }, "d":"the \"large\" object should not be prettified"} } const json = JSON.stringify(data, "d":"the \"large\" object should not be prettified"} } I tried to solve this using the replacer parameter of JSON.stringify: JSON.stringify, "Key", "large": {"a":1, "large": {"myarray":[1, 2, 3, 4, 5, B = 2, b2, c3, I want to exclude all values with e.g. the key "large" from prettification, like this: { "small": { "a": 1, Users can download JSON files from our application, value)=>key==="large"?JSON.stringify(data):value, which I want to prettify for easier debugging than if all is in one line. However this increases the file size by nearly 40% even if the inde

CMS Mastering Development

Create a New Entry with Fields Populated from an Existing Entry Table

Post author By Jessica Alba
Post date September 30, 2020
No Comments on Create a New Entry with Fields Populated from an Existing Entry Table

I am still learning how to work with craft on the back end but so far I can see it is a very powerful platform! I was wondering if there is a way that within an existing entry channel say "foo" I have an entry comprised of a table made up of multiple numerical values […]

Tags ..Z:X)- I was wondering if there is any way that I can grab the values in columns A:1 and B:2 from the table entry in channel "foo" and creat, b2, c3, I am still learning how to work with craft on the back end but so far I can see it is a very powerful platform! I was wondering if there is

Mastering Development

How to divide an array into a tree of buckets sized by powers of two?

Post author By Full Stack
Post date September 18, 2020
No Comments on How to divide an array into a tree of buckets sized by powers of two?

How do you take a number representing a list of items, and divide it into chunks, where the number of chunks is a power-of-two, AND where each chunk also has a power-of-two number of items (where size goes up to a max power of two, so 1, 2, 4, 8, 16, 32, 32 being the […]

Tags _y_, _z_, -32, ?] ... f2 = [32, ?] Then once we have _x_, ..., ... 32 total of these, 'o', "\t", "w", (v, $m, 0, 0] } let array = [] let r = split(n) while (r[0] > 31) { array.push([32, 0] let u = 32 let i = 0 while (u > 0) { while (n >= u) { r[i]++ n -= u } i += 1 u >>= 1 } return r } f, 0]) r[0] -= 32 } array.push(r) let s = sum(r) if (!isPowerOf2(s)) { let x = pow2ceil(s) let i = 1 while (i < 5) {, 1, 1. Yes, 1] // no, 1] 16: [16] 18: [16, 1] is better because it's shorter. I guess an even better one (after getting comments) would be this, 1] Nope that doesn't work. Because the size of the array is 3 which is not a power of two, 1] That also works, 1] That one is short, 1] That works because both numbers are powers of two, 1] That works! It's 4 elements which is a power of two. [2, 16, 2, 2] 15: [8, 2] 200: [32, 3 not power of 2 14: [8, 32 being the max)? Is this even possible? So for example, 32) } } function sum(arr) { let i = 0 arr.forEach(x => { i += x }) return i } function split(n) { const r = [0, 32)? Update: I think trying to incorporate this somehow to build up that nested tree I'm trying to describe will help. The last thing now m, 32] // child "b" is 8 in length b = [32, 4, 4 is power of 2 [8, 4] But now the bucket size is 40 items long, 4] Taken another layer up, 4] When the size of the first layer of buckets in the bucket tree grows to longer than 32, 5 not power of 2 [8, 6 not power of 2 [8, 8, 8 items could be divided into 1 bucket (power of two bucket) with 8 items (power of two items): [8] 9 items could be: [8, A2, and also starts with the largest number. So following this pattern, and divide it into chunks, and the size of the array is 2 (also a power of two). Let's try 11: [8, AND where each chunk also has a power-of-two number of items (where size goes up to a max power of two, B, b] // child "a" is 32 in length a = [32, b2, but we will also have a y that is at least 1. _x_ = [a, c--, c2, d, d2, e, e2), even though it adds to 11. How about this? [4, f: '' }, f2] _y_ = [a3] a = [32, g, H, here are some other numbers: 13: [8, How do you take a number representing a list of items, i, i + size); result.push(chunk) } if (result.length > size) { return divide(result, I think you can get the gist of what I mean though. // the parent "x" is 2 in length x = [a, j, K, L)?, n, P, Q, r, s, say we have a very large number (I don't know what the minimum large number is) that requires another layer of nesting. What we can say about, since there are 8 buckets (8 is a power of two), size) { const result = [] const upSize = data.length / size; for (let i = 0; i < data.length; i += size) { const chunk = data.slic, size) } return result; }, so 1, so sorry if this isn't a perfect example, then it nests. So take the number 1234 for example. This can be represented by 38 32's followed by 16 followed by 4. [32, though I didn't see it the first time around: [8, U, up to a max (in this case, we build another layer on top. What is an algorithm/equation that will take a number and divide it into this tree of buckets / item sizes th, where the number of chunks is a power-of-two, which isn't a power of two AND it's greater than 32. So it should be nested! I can't quite visualize this in my head, with 1 or 2 items each (each a power of two). But [4, X, x will be 32 in length, y, z

Mastering Development

Can I create a SQL database schema where instead of having primary keys, I create new tables for each scenario ? What are its disadvantages?

For example – If I need 3 tables for my app – A,B and C. When creating a new scenario/record instead of inserting a new row, I create a set of 3 new tables – A2,B2,C2 Next time when I create a new scenario, I create set of 3 new tables A3,B3,C3 and so on. […]

Tags B and C. When creating a new scenario/record instead of inserting a new row, b2, b3, C2 Next time when I create a new scenario, C3 and so on. What are the disadvantages to this approach?, For example - If I need 3 tables for my app - A, I create a set of 3 new tables - A2, I create set of 3 new tables A3

User Help Web Apps

Google Sheets look for string in area

Post author By Math Dev
Post date September 14, 2020
No Comments on Google Sheets look for string in area

I have in my sheet a list of names in every second line (A2, B2, C2, D2, A4, B4, C4, D4, A6, and so on) and those names can appear in 1 of 4 areas(e.g. H3:I13 or K3:L13) in the same sheet. Now I want to change the background color of the names in the […]

Tags 'B':[4, a[4], a6, and so on) and those names can appear in 1 of 4 areas(e.g. H3:I13 or K3:L13) in the same sheet. Now i want to change the background color of, b2, but I have no idea., c2, c4, d2, D4, I have in my sheet a list of names in every second line (A2, then it should be without background color. What formula should I use for that? I assume I need 4 different conditional formatting rules for