Tag: 7

How to get individual stats from a sports dataset of matches in pandas (convert list of lists to dictionary?)?

Post author By Full Stack
Post date April 8, 2020
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I have a CSV dataset of tennis match results in winner, loser format that has similar structure to this one: https://www.kaggle.com/jordangoblet/atp-tour-20002016 I want to create another table that will show number of wins, losses, days since last match, average serve percentage etc. per player. A friend suggested trying something like this: games = [ [“Elliot”, […]

Tags 'losses': 0, 'score': 1000.0, "Brendan", "Maya", "Omid", ] players = {} K = 32.0 game_number = 1 for game in games: p1name, } if p2name not in players: players[p2name] = { 'wins': 0, } more code... ... print('Rank Player Elo Wins Losses') rank = 1 for player, ~Winner, ~winner_id, 10, 6, 7, 8, average serve percentage etc. per player. A friend suggested trying something like this: games = [ ["Elliot", days since last match, Elliot, I have a CSV dataset of tennis match results in winner, item[0], Jamie, key=lambda item: (item[1]['score'], loser, loser format that has similar structure to this one: https://www.kaggle.com/jordangoblet/atp-tour-20002016 I want to create another table th, loser_delta, loser_elo, loser_id, loser_points_won, loser_serve_hold, loser_serve_points_won, loser_set_1, loser_set_2, loser_set_3, loser_set_4, loser_set_5, loser_sets, loser_true_serve_pct = game where all the above are the column names in my original df but I get this error: NameError: name "game_id" is n, losses, p in sorted(players.items(), p['losses'])) rank += 1 I tried to tweak this code to my needs by making my df a list of lists: lol = df.values.tolist() players = {}, p['score'], p['wins'], p1score, p2name, p2score = game if p1name not in players: players[p1name] = { 'wins': 0, player, reverse=True): print('%4s s %7.1f %5s %7s' % (rank, round_match, the variables = game should be just in one line. But you're welcome to comment if there is a better solution to achieve what I described in t, tournament_date, tournament_id, tournament_name, winner_delta, winner_elo, winner_points_won, winner_serve_hold, winner_serve_points_won, winner_set_1, winner_set_2, winner_set_3, winner_set_4, winner_set_5, winner_sets, winner_true_serve_pct

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Create 2 subdivs of child Div and add Dynamic unique ID on Appended Child Divs?

Post author By Full Stack
Post date April 8, 2020
No Comments on Create 2 subdivs of child Div and add Dynamic unique ID on Appended Child Divs?

I am currently building a blackjack game and each time I press “hit”, I run this function which appends divs that represents a card pulled from a deck. I am able to set a ID to the div, but I want each ID to increment in value… So div1, div2, div3. Currently, each div gets […]

Tags "&clubs"]; var values = ["2", "&diams", "A"]; var deck = new Array(); function createDeck() { deck = new Array(); for (var i = 0; i < values.length; i++) { for (var x = 0; x, "id_Here"); } So Once i create each card, "id": i, 10, 3, 4, 5, 6, 7, 8, 9, but I want each ID to increment in value... So div1, div2, div3. Currently, each div gets the same ID, Hand: hand }; players.push(player); } } function deal() { for (var i = 0; i < 2; i++) { for (var x = 0; x < players.length; x++), hearts, I am currently building a blackjack game and each time I press "hit", I run this function which appends divs that represents a card pulled from a deck. I am able to set a ID to the div, I want the "Hello" to be replaced with the cards value and the cards suit. The card value and Card suit can be obtained using this deck / pl, j, K, points: 0, Q, Suit: suits[x], Weight: weight }; deck.push(card); } } } var players = new Array(); function createPlayers(num) { players = new Array(); for, which would be useless when trying to add values to each card. Another issue I am having is trying to add 2 more sub divs ( each with unique, x); updatePoints(); } } updateDeck(); } If anyone would have a more simplified solution for the code listed above and how to g

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Evaluating Specific Numbers Within a 2D Array

Post author By Full Stack
Post date April 8, 2020
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I’m trying to get any 2D array, and then evaluating numbers in a 2×2 square and seeing which one is the highest number. I keep getting an ArrayIndexOutOfBoundsException: 4. I mapped out how the code would execute but I don’t see how I am getting out of the bounds of the array. Anyone see the […]

Tags 1, 2, 3, 4, 5, 5}}; int[][] areaTwo = { {3, 7, 8, 8}}; ArrayList one = highest(areaOne); System.out.println(Arrays.deepToString(one.toArray())); ArrayList two, and then evaluating numbers in a 2x2 square and seeing which one is the highest number. I keep getting an ArrayIndexOutOfBoundsException: 4., area[i][j+1], area[i+1][j], area[i+1][j+1]}; int peak = square[0]; for(int k = 0; k , I'm trying to get any 2D array

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Find intersection of dictionary values list

Post author By Full Stack
Post date April 8, 2020
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I have two dictionaries with the same keys, while the values are variant: a = {1: [1, 2, 3, 4, 5], 2: [6, 7, 8], 3: [1, 3, 5, 7, 9]} b = {1: [2, 3, 4, 7], 2: [6, 7], 3: [1, 3, 15, 10]} I’m trying to get the intersection under the same […]

Tags 10, 10]} I'm trying to get the intersection under the same keys. I want this output: {1: [2, 15, 2, 2.6, 3, 3.1, 3]} I tried with this command but the result is wrong: dict(zip(a.keys() and b.keys(), 4, 5, 7, 8, 9]} b = {1: [2, a.values() and b.values())) output: {1: [2, I have two dictionaries with the same keys, while the values are variant: a = {1: [1

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Find unique elements in numpy array based on another array

Post author By Full Stack
Post date April 8, 2020
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I have two numpy arrays for which I’d like to find the number of unique entries in x separated by the uniqueness array u. For instance the following two arrays would return a uniqueness score of 19. x = [1, 2, 1, 0, 3, 1, 2, 2, 4, 0, 0, 1, 3, 3, 2, 1, […]

Tags 0, 0] u = [1, 1, 2, 3, 4, 4}|=5 =1 =4 =1 =5 # ^ # +--- in other words: #, 5, 6, 7, 7] # =2 =1 |{0, apply it to x and add the result of len(np.unique(x[mask])), but I was hoping for a speedier (=w/o the loop) result as these arrays are largish (1000-5000 elements) in my real use case., derive the slicing mask, I have two numpy arrays for which I'd like to find the number of unique entries in x separated by the uniqueness array u. For instance the f

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Rotate binary search tree after every insert java

Post author By Full Stack
Post date April 7, 2020
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I need to rotate the tree after every insert, and it goes well while I add only lesser/greater value than his parent. I mean, if I insert 6-4-3 the resulting tree after the 2 rotations will be (read that like a level order print) 3-4-6 and it’s ok, but if I add a greater value […]

Tags "); if (root.parent == null) System.out.println("Parent : NULL"); else System.out.print, 5 and the result is 10-5-7-6-9-8 but it should be 5-7-6-9-8-10, 5}; for(int key : keys) { p.insert(key); } System.out.println("\n"); inorder(p.root); Sys, 6, 7, 8, 9, and it goes well while I add only lesser/greater value than his parent. I mean, but if I add a greater value than 3 (latest node added in that moment) like 5 the result will be 3-4-6-5, but they don't reach the root. For example, every element I put goes directly under the root, I need to rotate the tree after every insert, i try to insert 10, i want to change the root after every insert but it stays with 10. public class Prova1 { private Node root=null; public class Node { i, if I insert 6-4-3 the resulting tree after the 2 rotations will be (read that like a level order print) 3-4-6 and it's ok, int value) { Node prevNode = node; if(node.value>value) { if(node.left==null) { node.left = new N, Node parent) { int temp = node.value; node.value = parent.value; parent.value = temp; } public void climbRi, node.left); climbRight(node); } else { addNode(node.left, node.right); climbLeft(node); } else { addNode(node.right, parent; Node(int value){ this.value = value; this.left = null; this.right = null; this.parent = null;, right, so it doesn't rotate until I add another value lesser than root. How can i solve it? This is the code: EDIT: I added a swap method and chang, value); } } } public void swapKey(Node node, value); } } else if(node.value<value) { if(node.right==null) { node.right = new Node(value);, value); System.out.println("\n"); inorder(root); System.out.println("\n"); } } public void addNode(Node

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Concatenating rows using for loop

Post author By Full Stack
Post date April 6, 2020
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I want to concatenate the rows of a data frame. I have a start and end indices where the concatenation should start and end. df = pd.DataFrame(np.random.randint(0,50,size=(100, 4)), columns=list(‘ABCD’)) df.astype(‘str’) startLoop=[1,4,7,10,13,16] endLoop=[4,7,10,13,16,19] For example, if I have a data frame that looks like below: A B C D 3 14 15 7 2 9 7 […]

Tags 10, 13, 16, 16] endLoop=[4, 19] For example, 4, 50, 7, columns=list('ABCD')) df.astype('str') startLoop=[1, endLoop): for index, I want to concatenate the rows of a data frame. I have a start and end indices where the concatenation should start and end. df = pd.DataFra, if I have a data frame that looks like below: A B C D 3 14 15 7 2 9 7 2 9 3 0 7 3 11 3 6 11 10 6 2 . . ., in range(startLoop, index] + row But this is not working at all. Can anyone help me achieve this?, index] = df.iat[row, row in df.iterrows(): df.iat[row, size=(100

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Recoding data from 1,1,1, to 1,2,3

Post author By Full Stack
Post date April 6, 2020
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So I have this dataframe. Under the column potential_child, I want to recode the values so that the oldest child == 1, the second oldest == 2, third oldest == 3, etc. I have the ages of the children, but I am floundering how to do this exactly. DHS1 <- structure(list(person_id = c(1, 2, 1, […]

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How to create a list in Power Query from the listed values in Excel sheet, if it has a range

Post author By How To
Post date April 6, 2020
No Comments on How to create a list in Power Query from the listed values in Excel sheet, if it has a range

I am trying to modify the Excel’s Power Query with specific rows to keep by using function Table.SelectRows(…). I have the list with numbers of rows to keep and it’s working fine, however, I can’t make that list dynamic. What I want to achieve is having a cell in Excel sheet which has rows listed […]

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How to force zero (0) to the center of an axis in matplotlib

Post author By Full Stack
Post date April 5, 2020
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I’m trying to plot percent change data and would like to plot it such that the y axis is symmetric about 0. i.e. 0 is in the center of the axis. import matplotlib.pyplot as plt import pandas as pd data = pd.DataFrame([1,2,3,4,3,6,7,8], columns=[‘Data’]) data[‘PctChange’] = data[‘Data’].pct_change() data[‘PctChange’].plot() This is different from How to draw axis […]

Tags 2, 3, 4, 6, 7, 8, but rather, change the limits of the y axis such that the zero is in the center. Specifically in a programmatic way that changes in relation to the data., columns=['Data']) data['PctChange'] = data['Data'].pct_change() data['PctChange'].plot() This is different from How to draw axis in the midd, I'm trying to plot percent change data and would like to plot it such that the y axis is symmetric about 0. i.e. 0 is in the center of the ax