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Lookup and merge using lists in python

Post author By Full Stack
Post date April 10, 2021
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Given 2 lists of same length ,the operation I want to perform is lookup in second list and merge the result in original list. However, the key and value of lookup changes. # Input data = ["A", "ReplaceMe", "ReplaceMe", "A", "ReplaceMe", "C"] replace_values = ["Version1", "", "", "Version2", "", ""] # Expected output [‘A’, ‘Version1’, […]

Tags 'C'] def replace_elements(dataset, "", ""] # Expected output ['A', "C"] replace_values = ["Version1", "ReplaceMe", \"version\":2}", a, but has O(n) complexity. Can I use dict to get this done in a faster way ?, Given 2 lists of same length, i in enumerate(dataset): if i == "A": replace_by = replacements[j] if i == "ReplaceMe": dataset[j] =, replacements): for j, the key and value of lookup changes. # Input data = ["A", the operation I want to perform is lookup in second list and merge the result in original list. However, version=1

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Split CSV File, Name Based on Contents, Save As HTML

Post author By Full Stack
Post date April 7, 2021
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[Click here to view table][1] I think this is a simple task, but I’m a biologist who only knows a teeny bit of code and after several days of trying to figure this out, I’m at my wit’s end :'( Using terminal on a mac. I have a CSV file that I want to split […]

Tags `info`, `status`, :col_sep => ", :headers => true, :skip_blanks => true) do |row| id, ", "", "Jacquemontia reclinata, "Not choosy about lawn, [ 'name' => $row[0], [Click here to view table][1] I think this is a simple task, ++c) sub(/csv[.]/, Agapostemon, Agapostemon males have black and yellow stripes on the abdomen. A. sericeus males have a tooth on its hind femur. Female has metallic green a, Agapostemon males have black and yellow stripes on the abdomen. A. splendens have brown wings. The female abdomen is often somewhat bluish., Agapostemon males have black and yellow stripes on the abdomen. Females have a yellow band on the lower margin of the clypeus., All other Agapostemon species, and after each I made a little comment on why it did not work. More Info Based on Comments Here are some lines copied from the text file: G, April-October, as long as flowers are present", asks to "display all possibilities (y/n)" I tried returning "y" and "yes" and both times it says my answer is not recognized Attempt #2 file_, Brown-winged Striped-Sweat Bee, Bug Guide, but I'm a biologist who only knows a teeny bit of code and after several days of trying to figure this out, but it's hard to tell in the terminal window: f = File.new("bee_key_fact_sheet .csv") f.each_line { |line| puts line } Currently playi, Common Name, deep, Discover Life, Excavates into deep burrows in ground nests, file) print header > file } {f.write}' File.close #AWK not recognized, file['name']), Flowers, Ground-nester in loamy soils, Ground-nester in sandy soils, Honey-tailed Striped-Sweat bee, https://bugguide.net/node/view/70932, https://bugguide.net/node/view/74478, https://bugguide.net/node/view/83023, https://explorer.natureserve.org/Taxon/ELEMENT_GLOBAL.2.928401/Agapostemon_melliventris, https://www.discoverlife.org/20/q?search=Agapostemon+melliventris, https://www.discoverlife.org/mp/20q?search=Agapostemon+sericeus, https://www.discoverlife.org/mp/20q?search=Agapostemon+splendens, https://www.sharpeatmanguides.com/sweat-bees, I'm at my wit's end :'( Using terminal on a mac. I have a CSV file that I want to split into separate files by row (162 rows) and I want to, Identification, March-December, melliventris, N'EST', other, row[1] unless (id =~ /#/) names = name.split end #This returned nothing Thank you so much for taking any time to read this. [1]: https://i.st, Secure G5, sericeus, Silky Striped Sweat Bee, Similar Species, Sociality, solitary, species, splendens, This is the most common Agapostemon found in the southeast region, Time of year this bee is seen, underground excavation", Updated code I've tried based on comments. This worked and I think it's heading in the direction I want, Wide variety of plants

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How to copy a string to a 2D array in c

Post author By Full Stack
Post date April 7, 2021
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I want to create a c program that when the user enters some words like this: "some,words, in, c, proramming." the program save words in the string "str", then it creates Dynamically a 2D array and copies the words into the 2D array: #include <stdio.h> #include <stdlib.h> #include <string.h> #include <strings.h> #include <math.h> #include <conio.h> […]

Tags '&& *arr!='.'){ letters =letters+1; } ++arr; }while(*arr); return letters; } int wordCount(char *arr), '||arr[i]=='.'){ space++; } if(space>0){ words++; space=0; } } return word, 'three'), 'two'), "", } */ freeMememory(ptr, &arr); int *words = wordCount(arr); int *letters = lettersCount(arr); row=words; column=letters; int **ptr = (int **)mal, c--, cammas)?, column; scanf("%[^\n]s", Four, four." ptr = { "some", I want to create a c program that when the user enters some words like this: "some, In, int row){ for(int i=0;i<row;i++) free(array[i]); free(array); } int lettersCount(char *arr){ int space=0, j, letters=0; do{ if(*arr !=' '&& *arr!='\t' && *arr!=', proramming." the program save words in the string "str", row, row); return 0;} So any ideas how to copy only the words from the string into the 2D array without copying (periods, spaces, then it creates Dynamically a 2D array and copies the words into the 2D array: #include #include #include #i, words, words=0; for(int i=0; arr[i]!='\0'; i++){ if(arr[i] ==' '|| arr[i]=='\t'|| arr[i]=='\n'||arr[i]=='

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What is required to make this treemap plot work?

Post author By Full Stack
Post date April 6, 2021
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Been trying to get treemap to work but the output is blank and not sure why. If I take an example from the web and place it into my code the the output works fine – but when I try to use my data it does not output. The sample code is.. library(plotly) labels = […]

Tags "", "14", "30") fig <- plot_ly( type="treemap", "B1") values = c("11", "B2") parents = c("", 12, 13, 15, 20, A[1], a[4], A2, A3, a5, b1, Been trying to get treemap to work but the output is blank and not sure why. If I take an example from the web and place it into my code the, color = fgpct )) %>% hc_title(text = "Continent- Country Deaths") %>% hc_subtitle(text = "Deaths R, Country.x) %>% summarise(Deaths = sum(Deaths))## %>% Continents_tmap <- data.frame(Continents_tmap) labels <- Continents_tmap$Country.x, fgpct = sum(Deaths)) %>% hchart("treemap", hcaes( name = Country.x, I can only assume it is my data frame and I don't know why as I have tried all I know. My data Code.. Continents_tmap % group_, labels=labels), marker=list(colorscale='Reds')) }) Regards I got it to work using highchart but still not in plotly - my code for highchart is output, marker=list(colorscale='Reds')) fig The data source I am using is data frame and when I apply the data sources to the above example it simp, parents=parents, plotlyOutput("tmap1") ) My server side code.... output$tmap1 <- renderPlotly({ plot_ly( type="treem, value = pts, values=values

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How to replace and insert a new substring in python?

Post author By Full Stack
Post date April 3, 2021
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This is a working code and mabybe not very effcient code to replace a substring with another substring previously modified Input string : text = ["part1 Pirates (2006)", "part2 Pirates (2006)" ] Output string: Pirates PT1 (2006) Pirates PT2 (2006) It has to replace substring like ‘part1’ ‘part2 an so on , with ‘PT’ and […]

Tags 'pt' or 'part 2' and so on EDIT: I assumed this string was the same, "", "part 2 Pirates (2006)" ] I dont know how to extract the integer next to 'part', "part2 Pirates (2006)" ] Output string: Pirates PT1 (2006) Pirates PT2 (2006) It has to replace substring like 'part1' 'part2 an so on, but it doesn't., newStr, partStr) #End print (result) but when the list is like this text = ["pt1 Pirates (2006)", sry How to solve ? "part 2 the day sports stood still (2021)" \w+ doesn't grab all the words, This is a working code and mabybe not very effcient code to replace a substring with another substring previously modified Input string : t, title) #Build a new string -------------------------> "PT1 (2006)" newStr = "PT" + intPartStr[0] + " (" + yearStr + ")" #Update ti, title) #Delete 'part' Substring --------------------> 'Pirates (2006) partStr = re.sub(r'part(\d+)', with 'PT' and copy it between title and year substring Code: #''''''''''''''''''''''''' # are there parenthesis? # def parenth(stringa):

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How to remove extra icon in ggplot legend

Post author By Full Stack
Post date March 26, 2021
No Comments on How to remove extra icon in ggplot legend

I do not have any NA values in my data set, but ggplot plots as if I do (red dot at top of legend). How can I remove these non-existent NA? I do not want NA in my legend. There are no NA’s in genera and that is where I’m having the issue. I have […]

Tags -0.121, -0.135, -0.274, -0.509, -1.065, -10.03, -12.09, -12.48, -12.76, -15.07, -3.63, -8.07, .17-.86, '0.41', '10.13.2020'], '10.21.2020'], '10.27.2020'], '10/1/2020', '20' => '25', '24 – 25', '56.9', '9/2/2020', 'December'], 'na', "-0.15", "", ""), "1/5/2021", "1/7/2021", "10/12/2020", "10/16/2020", "10/19/2020", "10/20/2020", "10/22/2020", "11/10/2020", "11/13/2020", "11/16/2020", "11/20/2020", "11/9/2020", "12-10-2020", "12/9/2020", "2/10/2021", "2/8/2021", "8/26/2020", "8/31/2020", "9/1/2020", "9/10/2020", "9/11/2020", "9/22/2020", "9/29/2020", "9/30/2020", "9/4/2020", "9/8/2020", "9/9/2020", "Aphanizomenon", "August", "CS Riyer Island", "CS S Lib Island", "Dolichospermum", "Franks Tract", "Geitlerinema", "January", "Lyngbya", "Microcystis", "mod low", "MR Bacon Island", "November", "October", "OR Holland Tract", "Oscillatoria", "Pseudananabaena", "Sac at Decker", "Sac Isleton", "September", "Sherman Lake", "SJR Big Break", "SJR Turner Cut", "very low", ] - I think this should be correct, {10: 19}, {11: 27}, {8: 19}, 0, 0.099, 0.102, 0.104, 0.108, 0.11, 0.113, 0.118, 0.125, 0.127, 0.129, 0.137, 0.144, 0.155, 0.158, 0.159, 0.169, 0.171, 0.192, 0.194, 0.211, 0.221, 0.293, 0.434, 0.449), 0.451, 0.499, 0.531, 0.648, 0.703, 0.807, 0.938, 1.002, 1.928, 1/8/2021, 10.45, 10.55, 10.83, 10L), 11.11, 11.17, 11.38, 11.84, 1105.03, 117.72, 11L, 12.95, 12/11/2020, 12L, 13.76, 14.05, 14.53, 14.9, 142.88, 15.78, 16.25, 16.57, 16=1.6%, 17.22, 19.75, 1e-04, 1L, 2.017, 2.054, 2.608, 20.04., 20.07, 20.37, 20.76, 220.79, 24.16, 27.23, 27.32, 27.66, 277.85, 2L, 3.843, 31.16, 32.64, 390.71, 3L, 4.427, 4.592, 40.99, 41.93, 5.43, 5.79, 5.93, 52.21, 52.25, 56.7, 59.91, 6.57, 6.62, 68.25, 68.53, 7.1, 7.18, 7.31, 7.37, 7.44, 7.76, 7.79, 7.83, 7.85, 7.94, 71.64, 8.14, 8.16, 8.31, 8.37, 8.57, 8.72, 8)) shell + scale_size(guide=FALSE) Site date word genera rank 76 SJR Turner Cut 8/26/20, 86.15, 86.64, 8L), 9.02, 9.36, 9.42, 9.44), 9.77, 90.58, 97.09, 99L, 9L, alpha=0.5) + scale_x_discrete(name = "") + scale_y_discrete(name = "") + theme(axis.text.x = element_text(face="bold", angle = 45, but ggplot plots as if I do (red dot at top of legend). How can I remove these non-existent NA? I do not want NA in my legend. There are no N, but I keep getting an error. shell <- ggplot(genera_month) + geom_point(aes(x = Site, but I need to show all months). Also tried case.complete. Also tried [!is.na(genera_month$genera), class = "data.frame", color = genera, date = c("9/8/2020", February, genera = c("", hjust = 1)) shell shell+scale_size_continuous(range = c(4, I do not have any NA values in my data set, levels=c("February", Low, mc = c(46.2, mcw = c(0.186, Month = c(9L, Rank = c("", rank = c(NA, row.names = c(NA, sizerank, word = c("September", y = factor(word

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Vectorization of loops with geocoding Python

Post author By Full Stack
Post date March 23, 2021
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I have a long list of addresses and I need to geocode them in coordinates and I’m doing it with geopy in Python. I’ve written a loop in order to find for each observation the corresponding coordinates. In this loop I also take into account the fact that sometimes there are connection time out problems […]

Tags 'progress', "", "ArcGIS"]) # If we failed with an error like a timeout we will try the address again after we wait 5 secs except Exception as e:, "ArcGIS"]) except Exception as e: print("Failed with error {} on address {} again.".format(e, "None"]) failed += 1 else: print("Successfully found it.") results.append([addres, "None"]) print("Gave up on address: " + address) failed += 1 else: results.append([address, address in enumerate(df["address"]): # Print the status of how many addresses have be processed so far and how many of the failed. if, address)) failed += 1 results.append([address, address)) try: time.sleep(5) g = geocode_address(address) if g is None: print("Di, attempts_remaining, attempts_remaining-1, attempts_to_geocode, error, FAILED, g.latitude, g.longitude, I have a long list of addresses and I need to geocode them in coordinates and I'm doing it with geopy in Python. I've written a loop in order, I managed to geocode 1000 obs in half an hour, like vectorization. I could reduce the waiting time to re-try but then more attempts will fail This is an example code: import pandas as p, so I was wondering if there is a way to speed up, total_failed)) failed = 0 # Try geocoding the addresses try: g = try_address(address, wait_time) if g is None: results.append([address, wait_time): g = geocode_address(address) if g is None: time.sleep(wait_time) if attempts_remaining > 0: t, wait_time+wait_time) return g start_index = 0 # How often the program prints the status of the running program status_rate = 100 # How m

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Can we use dynamic array data() as a longopts parameter in getopt_long function?

Post author By Full Stack
Post date March 17, 2021
No Comments on Can we use dynamic array data() as a longopts parameter in getopt_long function?

I am trying to create an argument parsing class on C++ that will be using getopt_long function. So basically I want the longopts argument can be created dynamically. This code, that using static array for longopts argument will work: int main(int argc, char **argv) { while (true) { static struct option long_options_static[] = { {"a", […]

Tags 'a'}; long_options_vec[1] = {"b", 'b'}; int option_index = 0; char c = getopt_long(argc, "", }; int option_index = 0; char c = getopt_long(argc, &option_index); } return 0; } But this, &option_index); } return 0; } From the getopt_long manual, 0, a, am I missing something, argv, B, char **argv) { while (true) { static struct option long_options_static[] = { {"a", char **argv) { while (true) { std::vector long_options_vect(2); long_options_vec[0] = {"a", I am trying to create an argument parsing class on C++ that will be using getopt_long function. So basically I want the longopts argument can, it only stated that longopts is a pointer to the first element of an array of struct option... So in theory, long_options_static, long_options_vect.data(), required_argument, that using static array for longopts argument will work: int main(int argc, that using std::vector will compile but not work as expected: int main(int argc, using any kind of containers such as std::vector or std::array and then passing the storage's pointer is possible right? But I get unrecogniz

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ArcPy – Get Date as parameter value and calculate Date field

Post author By Server Questions
Post date March 10, 2021
No Comments on ArcPy – Get Date as parameter value and calculate Date field

In my ArcPy script I have an input parameter for the Date, so the user is asked to input a date value (time is not needed) using the data type GPDate. In the script I calculate a new field, field data type DATE, which should include for all features the date that the user entered. […]

Tags "", "DATE") I already tried 100 varieties with datetime, (myfield, ['date', but either I get an error indicating "unexpected EOF while parsing" or that the value cannot be written to the attribute table., field data type DATE, In my ArcPy script I have an input parameter for the Date, python3, so the user is asked to input a date value (time is not needed) using the data type GPDate. In the script I calculate a new field, strftime and different formatting of the date (my default input is dd.mm.YYYY), which should include for all features the date that the user entered. I cannot find a way how to populate this new field with the value of t

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Split a cell with coordinates into two columns with Latitude and Longitude only

Post author By Full Stack
Post date March 9, 2021
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I am trying to split a cell with coordinates like 01.00000, 02.00000; 03.00000, 04.00000; 05.00000, 06.00000 into two columns LAT and LONG. In the first column, all Latitude In the second column, all Longitude Like | Col A | Col B | Col C | |————————————————————|—————————-|—————————-| | 01.00000, 02.00000; 03.00000, 04.00000; 05.00000, 06.00000 | 01.00000,03.00000,05.00000 […]

Tags ", "", ")))) But I don’t know how to combine the rest now (I don’t really understand how it would be possible to combine everything together with C, "LNG LTD", 02.00000; 03.00000, 03.00000, 04.00000, 04.00000; 05.00000, 05.00000 | 02.00000, 06.00000 | 01.00000, 06.00000 | I use the division formula if only one coordinates are written =ArrayFormula(IF(ROW(B1:B)=1, 06.00000 into two columns LAT and LONG. In the first column, all Latitude In the second column, all Longitude Like | Col A | Col B | Col C, I am trying to split a cell with coordinates like 01.00000, IF(ISBLANK(A1:A), SPLIT(A1:A