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## How to use a cut in prolog to find the number of daughters?

Exercise: Observe the family structure below where each person has a gender specification as their third parameter (m = male, f = female). Use a cut to write the predicate numDaughters(L, Count) in such a way that family(Husband, Wife, Kids), numDaughters([Husband, Wife|Kids],X) lists each family in the database and the number of daughters in each […]

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## how to show the results of two different functions, working with lists and sapply? or for loop?

For each unique id I’m taking the first 3 rows (studies) to predict the remaining studies in that id. I was able to write the code but I couldn’t show the results. id <- c(1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 3, 3, 3, 3) year <- c(1978, […]

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## How can I find the largest increase in value of the elements of this list and then return the corresponding year and actual value it increased by

MIDYEAR_POPULATION = [(1971, 21962032), (1972, 22218463), (1973, 22491777), (1974, 22807969), (1975, 23143275), (1976, 23449808), (1977, 23725843), (1978, 23963203), (1979, 24201544), (1980, 24515667), (1981, 24819915), (1982, 25116942), (1983, 25366451), (1984, 25607053), (1985, 25842116), (1986, 26100278), (1987, 26446601), (1988, 26791747), (1989, 27276781), (1990, 27691138), (1991, 28037420), (1992, 28371264), (1993, 28684764), (1994, 29000663), (1995, 29302311), (1996, 29610218), (1997, […]

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## How can I find the largest increase in value of the elements of this list and then return the corresponding year and actual value it increased by

MIDYEAR_POPULATION = [(1971, 21962032), (1972, 22218463), (1973, 22491777), (1974, 22807969), (1975, 23143275), (1976, 23449808), (1977, 23725843), (1978, 23963203), (1979, 24201544), (1980, 24515667), (1981, 24819915), (1982, 25116942), (1983, 25366451), (1984, 25607053), (1985, 25842116), (1986, 26100278), (1987, 26446601), (1988, 26791747), (1989, 27276781), (1990, 27691138), (1991, 28037420), (1992, 28371264), (1993, 28684764), (1994, 29000663), (1995, 29302311), (1996, 29610218), (1997, […]