Tag: 18

Creating custom/more distance of ticks x axis in ggplot R

Post author By Full Stack
Post date April 13, 2021
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Please find my code below: packages <- c("ggplot2", "dplyr", "quantreg", "officer","tidyverse","here","glue","rvg","viridis","scales") install.packages(setdiff(packages, rownames(installed.packages()))) lapply(packages, require, character.only = TRUE) data <- read.csv(file=’Spiderplot_data.csv’, header=TRUE) Progressed <- as.factor(data$Progression) Response <- as.factor(data$X) Response <- factor(data$X, levels = c("Progressive Disease", "Stable Disease", "Partial Response", "Complete Response")) highlight_df <- filter(data, Progression == 1) p <- ggplot() + geom_line( data, mapping = […]

Tags "14", "Complete Response")) highlight_df <- filter(data, "here" ], "Partial Response", "quantreg", "require": {} }, "rvg", "scales") install.packages(setdiff(packages, "Stable Disease", "viridis", ) ) + scale_shape_manual( values = c(16, [ 75, 0.001)) ) + scale_y_continuous( name = "Percent Change in Lesion SLD (%)", 10, 12, 16, 18, 18) ) + scale_color_brewer( palette = "Set1" ) + scale_x_continuous( name = "Cycle", 2, 20, 30, 4, 40, 45], 50, 6, 65, 8, breaks = c(-1, breaks = c(0, but to no avail., character.only = TRUE) data <- read.csv(file='Spiderplot_data.csv', color = Response, color = Response ) ) + geom_point( data, dplyr, expand = expansion(mult = c(0, Glue, group = Study_ID, header=TRUE) Progressed <- as.factor(data$Progression) Response <- as.factor(data$X) Response <- factor(data$X, height = 5)) %>% # export slide ----- base::print( target = here::here( "demo_3.pptx" ) ) As you can see the distance between each, I am using the funciton wrong? Any help would be much appreciated. Orginal Image Image with scale_x_sqrt, is there a way to spread out the distance on the plot between 0-20 and make space between 20-40 smaller? As you can see I have tried to do t, labels = percent ) + ggtitle("Response Plot") p p_dml <- rvg::dml(ggobj = p) # initialize PowerPoint slide ---- officer::read_pptx(), levels = c("Progressive Disease", limits = c(-1, limits = c(0, mapping = aes( x = Cycle, officer, ph_location(width = 10, Please find my code below: packages <- c("ggplot2", Progression == 1) p <- ggplot() + geom_line( data, rownames(installed.packages()))) lapply(packages, shape = 18, shape = Progressed ) ) + geom_point( # Data set with just points highlight_df, size = 2.8, tidyverse, y = Change

Mastering Development

How can I retrieve programmatically from command line my SO rep and number of badges?

Post author By Full Stack
Post date April 12, 2021
No Comments on How can I retrieve programmatically from command line my SO rep and number of badges?

Orignal question My initial attempt was to run curl https://stackoverflow.com/users/5825294/enlico and pipe the result into sed/awk. However, as I’ve frequently read, sed and awk are not the best tools to parse HTML code. Furthermore, the above URL changes if I change my user name. Oh, this is my quick attempt with sed, written on multiple […]

Tags 'gold', "SILVER", *[0-9]* (gold|silver|bronze) badges).*/\1/p }' which prints 10, /bronze badges/{ /"reputation"/{ N N s!.*>(.*)</.*!\1!p } /badges/s/.*[^1-9]([1-9]+[0-9]*, 18, 22, 27 ] ] Is anybody aware of why is that?, 27 silver, 5, 7. In this respect, 968 5 gold badges 27 silver badges 56 bronze badge Obviously this script heavily relies on the peculiar structure of the specific HTML page, and 56 bronze badges, and I thought that I could use that to take multiply awarded badges into account. This kind of works, as I've frequently read, count: .award_count}) | group_by(.rank) | map([[.[0].rank], I've noticed that 18 is the is the number of silver badges I have if I don't consider those awarded multilple times, in the sense that running the following (fetch_user_badges is from Léa Gris' answer) generates the correct number of silver badges but the wr, map(.count) | add])' [ [ "bronze", not 5, Orignal question My initial attempt was to run curl https://stackoverflow.com/users/5825294/enlico and pipe the result into sed/awk. However, sed and awk are not the best tools to parse HTML code. Furthermore, the above URL changes if I change my user name. Oh, the most notable example being that I run N twice because I've verified that the reputation is two lines below the first line in the file con, therefore I've played around with jq and discovered that I can query for the award_count beside the rank, this is my quick attempt with sed, written on multiple lines for readability: curl https://stackoverflow.com/users/5825294/enlico 2> /dev/null | sed -nE ' /title="reputation"/

Mastering Development

Syntax Error: ‘return’ outside function: my indentations seem to be correct

Post author By Full Stack
Post date March 31, 2021
No Comments on Syntax Error: ‘return’ outside function: my indentations seem to be correct

So first of all im writing a program that will total up all of the values in a list / array and heres what i got so far def go( ann ): total = 0 for i in range(0,len(ann)): total = total+ann[i] return total print ( go( [-99,1,2,3,4,5,6,7,8,9,10,12345] ) ) print ( go( [10,9,8,7,6,5,4,3,2,1,-99] ) […]

Mastering Development

How to get key from the value of dictionary

Post author By Full Stack
Post date March 29, 2021
No Comments on How to get key from the value of dictionary

I have the following set of rules for grading system if 25 < score <= 30, grade = A. if 20 < score <= 25, grade = B. if 15 < score <= 20, grade = C. if 10 < score <= 15, grade = D. if 5 < score <= 10, grade = E. […]

Tags -23, 'B': [21, 'C': [16, 'd': 11, 'e': 6, 'otherwise') but it will give you the values. Is there any other mechanism that does the opposite, "14", 1, 10, 12, 13, 15, 17, 18, 19, 2, 20, 22, 24, 25, 27, 28, 29, 3, 30, 4, 5] } so while checking the score with values I want to return the key In python I've learned something like dict.get(term, 7, 8, 9, else). But I want to do it in different manner. for instance I want to declare a dictionary like below: gradeDict = { 'A': [26, f = 0, grade = A. if 20 < score <= 25, grade = B. if 15 < score <= 20, grade = C. if 10 < score <= 15, grade = D. if 5 < score <= 10, grade = E. if 0 <= score <= 5, grade = F. so I have to write a function which takes score as parameter and returns letter grade. So I can do this using selections(if, I have the following set of rules for grading system if 25 < score <= 30, ie: if we can pass the value in the get method it will return the key?

Mastering Development

How do I block certain websites which have XYZ in their URL?

Post author By Full Stack
Post date March 28, 2021
No Comments on How do I block certain websites which have XYZ in their URL?

I wanted to write some code which limits the usage of some websites such as Instagram completely blocks porn sites by blocking every site with words such as "porn" or "xxx" in the URL switches the computer off automatically at some times It all works out, except for the blocking websites part. I tried to […]

Tags 'r+') as file: content = file.read() for website in Liste: if website in content:, "gmail"] mittagspause_start = dt(now.year, "kisscartoon", "lichess", "looksmax", "mvtube", "tnaflix", "tube8", "xhamster", "xnxx", "xtube", "xvideos", "xxx", ] seltenwörter_url = ["instagram", 0) evening = dt(now.year, 12, 18, 20, 21, 30) if now = evening: print("Turning off computer") listeseltenerwörter = [] listeproblemwörter = [] for wort in proble, 30) mittagspause_ende = dt(now.year, 30) now = dt.now() noon = dt(now.year, and redirect as soon as there are some words in the URL, dailymotion, except for the blocking websites part. I tried to access the host file, Facebook, Hub, I wanted to write some code which limits the usage of some websites such as Instagram completely blocks porn sites by blocking every site w, it still doesn't work. I honestly dont know why I can still access the websites. I added it as top priority to the task scheduler, now.day(), now.month(), Outlook..), Vimeo).', with starting the computer as a trigger Thanks in advance guys!! from datetime import datetime as dt import re import os #imporitng every mo

Mastering Development

Compare two lists in Pandas Dataframe with different length

Post author By Full Stack
Post date March 23, 2021
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I have two dataframes with lists which I need to compare in order to know if one row is the same than the other and then add it. The two datasets are: Dataset 1 sex age zip_code 0 F 46 08204 [6, 40, 9, 44, 30] 1 F 40 08205 [33, 41, 48, 50, 30] […]

Tags -11, -23, -41, -48, .44, "14", [[ 87, 10, 100, 107] 1 1122 [33, 107] 1 F 40 08205 [33, 111], 114, 119, 120, 126, 127, 13, 140, 15, 154, 157] What I am trying to compare is that the list of the column "weeks" from dataset2 are in the list of of the column "weeks" from dataset, 16, 165, 167, 169, 17, 18, 21, 21] 3 F 60 08304 [37, 22, 23] 6 F 50 08921 [10, 24, 25, 27, 28, 29, 29] 5 M 42 08917 [9, 3, 30] [70, 30] 1 F 40 08205 [33, 30] 1101 [126, 30] 1122 [70, 30] 2 F 46 08206 [32, 31, 32] [126, 33, 34] [152, 36] [117, 37, 39, 39] Dataset 2 user_id weeks blood_levels 0 1101 [15, 4, 40, 42, 43, 45], 49] 4 M 24 08507 [32, 5, 50, 52] 7 F 37 10627 [41, 68, 69, 7, 72, 72] 2 2112 [4, 72] 2 F 46 08206 [32, 74, 74] 3 2200 [3, 76, 80, 9, 93, 96, 99], expected output: sex age zip_code weeks user_id blood_levels 0 F 46 08204 [6, I have two dataframes with lists which I need to compare in order to know if one row is the same than the other and then add it. The two dat, the "user_id" and "blood_levels" columns from dataset 2 should be added to Dataset 1. Thus

Ask Geographic Information System (GIS)

Column value as index in function

Post author By Server Questions
Post date March 8, 2021
No Comments on Column value as index in function

This comes from the solution of another question. I have a network of polylines representing a river network, where I am working to make a calculation at each point on the polyline, based on some of some information from the downstream segments. In the example here, I have 5 river segments, segments 1-5. Each segment […]

Tags -0.4, -1] [4, -11, -23, '<1', "14", "h0")) > df.res segment index ix ixc seg.dist net.dist up.dist y z n k segmentParent h h0 1 1 1 1 0, "h0")){ ctrl <- c(0, (0)Y, {1}; {2}, 0, 0.2) z <- c(1, 0.6, 0.8)", 1, 1)-(6, 10, 100, 110, 12, 120, 120) up.dist <- c(400, 13, 15, 16, 17, 17) df <- data.frame(segment, 18, 19, 2, 2)) > df segment index ix ixc seg.dist net.dist up.dist y z n k segmentParent 1 1 1 1 0 0 0 400, 20, 200, 21, 22, 24) seg.dist <- rep(c(0, 3, 30, 4, 40, 40 at the top), 400, 5, 50, 6, 60, 7, 70], 8, 80, 9, 90, and the distance from the network outlet, and updates h0 as that maximum h value. The calculation starts at segment 1, as all segment ids will be >1 and for all upstream segments, based on some of some information from the downstream segments. In the example here, diff(seg)) h <- list(h = numeric(), each = 5) index <- rep(1:5, finds the maximum h across all indices on that segment, H, h0 = 10, h0 = h.orig(segment, h0 = numeric()) j = 1 for(i in seq_along(seg)) { if(ctrl[i] > 0) { h0 = max(h[[1]][j:(i-1)]) j = i } h[[1]][i] <-, h0 is defined as the maximum h from the segment i-1. This isn't always the case as some segments serve as the parent for > 1 segment. The da, have a segmentParent value of 0. As the function stands now, I have 5 river segments, index, instead of just iterating based off of i. h is calculated for every point on segment 1, it looks like: h.orig <- function(seg, ix, ixc, K, k = 1500) %>% mutate(segmentParent = c(0, n, net.dist, or root, output = c("h", say $q'$, seg.dist), segmentParent, segments 1-5. Each segment has 5 nodes on it (index). The connection between nodes are dictated by the ix (giver) and ixc (receiver) value. T, so it shouldn't be too difficult to crawl up the network from there, stored in net.dist. The total distance upstream of each segment is stored in up.dist. y, the solution I am looking for would replace the i-1 linear referencing scheme for updating h0 and replace it with something that takes the se, then the parentSegment id will be < q. This is obviously incorrect but just to visual what I am thinking in terms of a solution: fun.new <-, then we move to segment 2 where the greatest value of h from segment 1 is used for the h0 value. Segment 3 is also based off the maximum h va, This comes from the solution of another question. I have a network of polylines representing a river network, times = 5) ix <- 1:25 ixc <- c(0, times = 5) net.dist <- c(0, up.dist, where h0 and h are initialized), where I am working to make a calculation at each point on the polyline, y, z just contains values for mapping. n and k are constants. I am trying to use the segmentParent value as an index of what h0 value to use in, z) %>% mutate(segment = factor(segment)) %>% mutate(n = 0.5

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Dynamic style using variable substitution

Post author By Server Questions
Post date March 1, 2021
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I need to use an array of values to define a style of the WMS dynamically. I understood that I must use the Variable substitution SLD. I’m be able to use env variable to change fill and stroke of a polygons layer and set one unique color to all the features. Problems comes when I […]

Arduino Ask Engineering

6 buttons useless box

i want to make a useless box with 6 buttons MY CODE // steppmm*moveX=240 #include <Stepper.h> int BUTTON_PIN[7] = {26, 27, 22, 23, 24, 25, 10}; int lastState = LOW; int currentState; float Stepmm = 250 ; float A = 0; float B = 0; int S1[0]; const int stepsPerRevolution = 200 ; int switchPos[9] […]

Tags -11, -23, 10}; int lastState = LOW; int currentState; float Stepmm = 250 ; float A = 0; float B = 0; int S1[0]; const int stepsPerRevolution = 200 ; i, 12, 15, 18, 21, 22, 24, 24}; Stepper myStepper(stepsPerRevolution, 25, 27, 3, 5); int stepCount = 0; void setup() { Serial.begin(9600); myStepper.setSpeed(180); for (int i = 0; i < 10; i++) { pinMode(BUTTON_PIN[i], 6, 7, 9, i want to make a useless box with 6 buttons MY CODE // steppmm*moveX=240 #include int BUTTON_PIN[7] = {26, INPUT_PULLUP); } moveX(2); while (digitalRead(BUTTON_PIN[6]) == 1) { //moveX(-1); Serial.println("a"); } moveX(1.5); while (digitalRead(BUTTO, which is of non-class type 'int [0]' S1.back(i); ^~~~ Stepper_Motor_1.3:50:8: error: request for member 'pop' in 'S1', which is of non-class type 'int [0]' S1.pop(0); ^~~ exit status 1 incompatible types in assignment of 'int' to 'int [0]'

Mastering Development

Need to generate output in the following format year, q1,q2,q3,q4 in the MS SQL server for below data

Post author By Full Stack
Post date February 28, 2021
No Comments on Need to generate output in the following format year, q1,q2,q3,q4 in the MS SQL server for below data

CREATE TABLE acquisition ( id INT PRIMARY KEY IDENTITY, company_name VARCHAR(100), cost_amount INT NOT NULL, acquired_at DATE NOT NULL ); INSERT INTO acquisition(company_name, cost_amount, acquired_at) VALUES (1,’HOFA’, 6850, ‘2010-01-17′), (2,’POGA’, 9256, ‘2019-09-04′), (3,’CUPU’, 9329, ‘2012-08-21′), (4,’BULO’, 5162, ‘2020-11-21′), (5,’GICE’, 5301, ‘2012-10-04′), (6,’TOSE’, 1790, ‘2018-09-30′), (7,’POWU’, 7183, ‘2019-05-21′), (8,’YEJO’, 1491, ‘2010-12-12′), (9,’XAMO’, 5974, ‘2010-03-23′), (10,’TEFA’, 9456, […]

Tags -11, -23, '2010-01-17'), '2010-03-23'), '2010-12-12'), '2012-06-29', '2012-08-21'), '2016-07-31'), '2016-08-17'), '2016-11-02'), '2018-09-30', '2019-01-08', '2019-02-17'), '2019-06-12'), '2019-10-30', '2020-07-06', '2020-11-21'), '5942', 'BITO', 'BULO', 'CUPU', 'DIFA', 'FIKE', 'GATI', 'GICE', 'GOCU', 'HOFA', 'KIRE', 'KULA', 'MILE', 'MOMU', 'POGA', 'POWU', 'ROKU', 'TEFA', 'TOSE', 'VAYA', 'XAMO', 'YEJO', "14", "1491", "2012-10-04", "2018-04-04", "2019-03-19", "2019-05-21", "2019-12-20", "2020-04-09", "5162", "5301", "riso", ['2019-09-04', >", 10, 1127, 12, 13, 15, 16, 17, 1790, 18, 19, 1969, 2, 20, 2020-02-26, 21, 22, 24, 2469, 2655, 2695, 2790, 3, 4, 5, 5478, 5974, 6, 6850, 6997, 7, 7113, 7183, 8, 8104, 9, 9256, 9329, 9456, 9578, 9633, acquired_at DATE NOT NULL ); INSERT INTO acquisition(company_name, acquired_at) VALUES (1, company_name VARCHAR(100), cost_amount, cost_amount INT NOT NULL, CREATE TABLE acquisition ( id INT PRIMARY KEY IDENTITY, Kali, volu"