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# Show that if \$X\$ is compact, and if \$A\$ is a closed subset of \$X,\$ then \$A\$ is also compact.

Show that if $$X$$ is compact, and if $$A$$ is a closed subset of $$X,$$ then $$A$$(with the subspace topology ) is also compact.

A HINT:

Use the subspace topology to relate open sets in $$A$$ with open sets in $$X;$$ somehow you need to find an open cover of $$X.$$

Still I am unable to solve it using the hints given, could anyone help me in solving it using the hints given?