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About solid state

I am bit confused in what will be voids present in hexagonal close packing.
In it there are total 6 atom,then I will calculate the tetrahedral voids from the knowledge that the
Tetrahedral hedral void is twice the no.of atoms present present in the unit cell and octahedral voids are same as the no.of atoms present.
Therefore, octahedral voids=6
Tetrahedral void=12
But that is not the correct answer. Why?

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